Java program to take a year as input and tells whether it's a leap year or not

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Following program shows you how take a year as input and tells whether it's a leap year or not.

import java.util.Scanner;

public class BasicMath5 {

    public static void main(String[] args) {

        System.out.println("Enter a year:");

        Scanner in = new Scanner(System.in);
        int input = in.nextInt();

        if (input % 4 == 0) {

            if (input % 100 == 0) {

                if (input % 400 == 0) {
                    System.out.println(input + " its a leap year");

                } else {
                    System.out.println(input + " its not a leap year");
                }

            } else {
                System.out.println(input + " its a leap year");

            }
        } else {
            System.out.println(input + " its not a leap year");

        }

    }

}

Output:

Example1:

Enter a year:
1980
1980 its a leap year

Example2:

Enter a year:
2001
2001 its not a leap year
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